Here in this program, we will code to find the sum of a special series which is 1+x+x^2+……+x^n. Here **x **is the variable and **n **will represent up to which power the sum will continue.

** C++ Program to find the Sum of series 1+x+x^2+……+x^n**

#include<iostream.h> #include<conio.h> #include<math.h> void main() { clrscr(); long float sum=1,x,n,i; cout<<"Here we will calculate the sum of series 1+ x + x^2+ ...+ x^n \n"; cout<<"Enter the value of x :"; cin>>x; cout<<"Enter the value of n: "; cin>>n; for(i=1;i<=n;i++) { sum += pow(x,i); } cout<<"The sum of the series is: "<<sum; getch(); }

**Output:**

Here we will calculate the sum of series 1 +x +x^2 +……+ x^n Enter the value of x: 5 Enter the value of n: 7 The sum of the series is: 97656

**Python Program to find the sum of series 1+x+x^2+……+x^n**

import math sum=1 print("Here we will calculate the sum of series 1 +x +x^2 +……+ x^n") x=int(input("Enter the value of x: ")) n = int(input("Enter the value of n: ")) for i in range(1,n+1): sum+=math.pow(x,i) print("The sum of the series is:", int(sum))

**Output:**

Here we will calculate the sum of series 1 +x +x^2 +……+ x^n Enter the value of x: 3 Enter the value of n: 4 The sum of the series is: 121