Here in this program, we will code to calculate the sum of a special series x + x^{2}/2 +x^{3}/3 + ……. +x^{n}/n, where x and n are two variables which value the user will enter.** **

**C++ Program to find the sum of the series x+x^2/2+x^3/3+…..+x^n/n**

#include<iostream.h> #include<conio.h> #include<math.h> void main() { clrscr(); long float sum=0,x,n,i; cout<<"Here we will calculate the sum of series x + (x^2)/2+ ...+ (x^n)/n \n"; cout<<"Enter the value of x :"; cin>>x; cout<<"Enter the value of n: "; cin>>n; for(i=1;i<=n;i++) { sum += pow(x,i)/i; } cout<<"The sum of the series is: "<<sum; getch(); }

**Output:**

Here we will calculate the sum of series x+x^2/2+…..+x^n/n Enter the value of x: 4 Enter the value of n: 5 The sum of the series is: 302.1333

**Python Program to find the sum of the series x+x^2/2+x^3/3+…..+x^n/n**

import math sum=0 print("Here we will calculate the sum of series x+x^2/2+…..+x^n/n") x=int(input("Enter the value of x: ")) n = int(input("Enter the value of n: ")) for i in range(1,n+1): sum+=math.pow(x,i)/i print("The sum of the series is:", sum)

**Output:**

Here we will calculate the sum of series x+x^2/2+…..+x^n/n Enter the value of x: 4 Enter the value of n: 3 The sum of the series is: 33.333