Program to Check Armstrong Number [C, C++, Python & Java]

This tutorial helps you know how to write a program to check whether a number is Armstrong or not. We will implement this program in C, C++, Python, and Java.

To write the program for the Armstrong number, you need to know the syntax of a programming language, while loop, if...else statement, and logic for an Armstrong number.

What is an Armstrong Number?

An Armstrong number is a number with n digits whose sum of digits raised to the power n equals itself.

For example, 153 is an Armstrong number because it is a 3-digit number, and the sum of each digit raised to the power 3 equals 153.

Here is an illustration:

(1) ³ +(5) ³ +(3) ³ = 1+125+27 = 153

C Program to Check Armstrong Number

#include<stdio.h>
#include<math.h>
int main()
{
   int num, m=0, power=0, x,temp;
   printf("Enter a Number: ");
   scanf("%d", &num);
   temp = num;
   while(temp!=0)
   {
      temp = temp/10;
      power++;
   }
   temp = num;
   while(num!=0)
   {
      x =num%10;
      m+= pow(x,power);
      num= num/10;
   }
   if(temp == m)
   printf("%d is an Armstrong number", temp);
   else
   printf("%d is not an Armstrong number", temp);
   return 0;
}

Output:

Enter a Number: 153
153 is an Armstrong number

C++ Program to Check Armstrong Number

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
   int num, m=0, power=0, x,temp;
   cout<<"Enter a Number: ";
   cin>>num;
   temp = num;
   while(temp!=0)
   {
      temp = temp/10;
      power++;
   }
   temp = num;
   while(num!=0)
   {
      x =num%10;
      m+= pow(x,power);
      num= num/10;
   }
   if(temp == m)
   cout<<temp <<" is an Armstrong number";
   else
   cout<<temp <<" is not an Armstrong number";
   return 0;
}

Output

Enter a number: 54748
54748 is an Armstrong number

Python Program to Check Armstrong Number

num = int(input("Enter a number: "))
temp = num
power = 0
m = 0
while(temp!=0):
    temp = temp//10
    power += 1

temp = num
while(num!=0):
    x = num%10
    m += x**power
    num = num//10

if temp==m:
    print(temp,"is an Armstrong number")

else:
    print(temp,"is not an Armstrong number")

Output

Enter a number: 153
153 is an Armstrong number

Java Program to Check Armstrong Number

import java.util.*;
import java.lang.*;
public class Main
{
   public static void main(String[] args)
   {
   int num, m=0, power=0, x,temp;
   Scanner sc = new Scanner(System.in);
   System.out.println("Enter a Number: ");
   num = sc.nextInt();
   temp = num;
   while(temp!=0)
   {
      temp = temp/10;
      power++;
   }
   temp = num;
   while(num!=0)
   {
      x =num%10;
      m+= Math.pow(x,power);
      num= num/10;
   }
   if(temp == m)
   System.out.println(+temp+ " is an Armstrong number");
   else
   System.out.println(+temp+ " is not an Armstrong number");
   }
}

Output:

Enter a Number: 
345
345 is not an Armstrong number

Conclusion

This was all about writing a program for Armstrong number in C, C++, Python, and Java. Once you know the logic of how to determine an Armstrong number, you can easily write and run the program. In addition, you must take care of the while loop to separate the digits of a number.

Refer to the above programs, and implement them in your system. If you face any difficulties, let us know via comments.

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