How to Get Open Port Banner in Python?

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How to Get Open Port Banner in Python?
vinaykhatri

Vinay Khatri
Last updated on June 14, 2024

    If you do not know how to check the open and close port of a target in Python, then please check out this tutorial first. In this tutorial, we will move a bit further and learn how to grab the open port banner and retrieve the information about the services that are running on those open ports.

    The Python libraries we will be using in this tutorial are the Python standard libraries socket and threading . Using the socket module, we will try to scan the open port and grab the service banner, which is using the by open port. With the threading module we will try to run multiple threads in our Python program so the port scanning can be performed faster.

    Both of these modules socket and threading comes pre-installed with Python, so we do not need to install them using the pip install command.

    For this tutorial, I will be scanning my local IP address, if you want to scan a specific domain, you first need to grab its IP address. To know how to get the IP address of a website in Python, click here .

    How to get an open port banner in Python?

    Now we will start with importing the socket and threading module.

    import socket 
    
    import threading

    Now let's define a Python function port_scanner(port) that will scan the specific port and print the open port number and its banner (if have any)

    def port_scanner(port):
        try:
            my_ip_address = socket.gethostbyname(socket.gethostname())  #get my ip address
    
           
            s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) 
            s.settimeout(0.5)
        
            #connect to the ip address port number
            s.connect((my_ip_address, port))
            try:
                service = s.recv(1024).decode()
                print(f"Port {port} is open[+] using service {service}")
            except:
                print(f"Port {port} is open [+]")
        except:
            pass

    The gethostbyname(socket.gethostname()) function will return my local IP address.

    socket.socket(socket.AF_INET, socket.SOCK_STREAM) function will initialize the socket Object s.
    The AF_INET parameter represents the IP4 address family, and SOCK_STREAM represent the TCP connection.
    settimeout(0.5) function will set a 0.5 seconds timeout. And it specifies that the connection should be made within 0.5 seconds else, it would be an unsuccessful connection and throw an error.
    connect((my_ip_address, port)) function will try to connect to the specified IP address port number.
    s.recv(1024) function will return the received data (if any) in bytes object.
    The decode() function will decode the recv() byte object into a readable string.
    If the recv() function does not return anything it will throw an error that will be handled by the internal except statement. In that case, we will only print the open port number, not the service.
    Now let's call the scanner_port() function using threading and scan the first 5000 ports, and check if any of the ports show its service banner.
    for port in range(1,5000):
        thread = threading.Thread(target=port_scanner, args=[port])
        thread.start()
    Now put all the code together and execute

    Python code to find Open Port banners

    import socket 
    import threading
    
    def port_scanner(port):
        try:
            my_ip_address = socket.gethostbyname(socket.gethostname())   #get user IP address
    
            #initialize socket 
            s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
            #set a connection timeout
            s.settimeout(0.5)
    
            #connect to the IP address port number
            s.connect((my_ip_address, port))
            try:
                service = s.recv(1024).decode()  #get the open port banner(if any)
                print(f"Port {port} is open[+] using service {service}")
            except:
                print(f"Port {port} is open [+]")
        except:
            pass
    
    
    for port in range(1,5000):
        thread = threading.Thread(target=port_scanner, args=[port])
        thread.start()

    Output

    Port 21 is open[+] using service 220-FileZilla Server version 0.9.41 beta
    
    Port 80 is open [+]
    Port 135 is open [+]
    Port 139 is open [+]
    Port 445 is open [+]
    Port 443 is open [+]
    Port 3306 is open [+]

    As you can see that, only Port number 21, which is a TCP UP port, is showing its banner service, and the rest of the open ports do not have any banner associated with them.

    Conclusion

    Let's sum up the above Python tutorial. In this tutorial, you learned how to get the open ports banner in Python using the socket and threading modules. Although we only use threading to pace up the execution speed of the program by running multiple threads concurrently, most of the tutorial is about the socket.

    The only thing we require to get the open port service banner is the socket recv() method. You can also check the open ports banner name of a website by specific the website IP address.

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